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A car is traveling due east at 25.0 m/s at some instant. (a) If its constant acceleration is 0.750 m/s2 due east, find its velocity after 8.50 s have elapsed.

User Kakar
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Final answer:

The car's final velocity after 8.50 seconds, given an initial velocity of 25.0 m/s and a constant acceleration of 0.750 m/s², will be 31.375 m/s towards east.

Step-by-step explanation:

In this Physics problem, we are asked to calculate the final velocity of a car that is traveling with an initial velocity to the east and has a constant acceleration in the same direction. The equation which is needed to solve this type of problem is v = u + at, where 'v' is final velocity, 'u' is initial velocity, 'a' is acceleration and 't' is time.

The initial velocity 'u' is 25.0 m/s east, the acceleration 'a' is 0.750 m/s2 east, and the time 't' is 8.50 s. By substituting these values into the equation, we have:

v = 25.0 m/s + (0.750 m/s2 * 8.50 s) = 25.0 m/s + 6.375 m/s = 31.375 m/s east.

Therefore, after 8.50 seconds, the car's velocity will be 31.375 m/s direction east.

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User Carlyne
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