Answer:
3.498 grams
Step-by-step explanation:
First, find the Molecular weight of Na2CO3:
Na2CO3 = (2×23) + 12 + (16×3)
= 46 + 12 + 48
= 106 g/mol
Second, input the known molecular weight of Na2CO3 and number of moles into the following formula:
Mass (g) = number of moles × molecular weight (Mr)
g = 3.3 × 10‐² mol × 106 g/mol
g = 3.498 or 3.5 grams
Hope it helps. Thanks!