Final answer:
The question relates to Gay-Lussac's Law. Using this law and the given information, we can calculate that the new pressure of the gas when it is cooled to 20.00⁰C at a constant volume will be approximately 290.2 kPa.
Step-by-step explanation:
The question basically deals with the concept of Gay-Lussac's Law, which is a principle in gas physics stating that the pressure of a gas is directly proportional to its absolute temperature, provided the volume remains constant. To solve this, we can use the formula: P1/T1 = P2/T2, where P denotes pressure and T is temperature (in Kelvin). Therefore, to find the new pressure, we can rearrange the formula: P2 = P1 * (T2/T1).
In this problem, convert the temperatures to Kelvin by adding 273.15 to each Celsius reading.
So, T1 is (30.00 + 273.15) = 303.15K and T2 is (20.00 + 273.15) = 293.15K.
The initial pressure P1 = 300.0 kPa. Substituting these values gives: P2 = 300.0 kPa * (293.15K/303.15K) = 290.2140 kPa. Therefore, when the gas is cooled to 20.00⁰C at a constant volume, the pressure is approximately 290.2 kPa.
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