Question

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Answer 1

E, 3.

Explanation:

Since both f(x) and g[f(x)] are quadratic polynomials, g(x) must also be a linear polynomial.

Let g(x) = Ax + B, where A and B are constants to be determined.

Then we have A[2x² - 3x + 1] + B ≡ x² - (3/2)x + 3.

=> A = 1/2 and B = 5/2.

Hence, f[g(-1)] = f[(1/2)(-1) + (5/2)] = f(2) = 2(2)² - 3(2) + 1 = 3. (E)