Question

assume that a watermelon dropped from a tall building falls y = 16t^2 ft in t seconds. find the watermelson's average speed durign the first 4 seconds of the fall

Answer 1

Answer: The watermelon's position during the fall can be described by the equation y = 16t^2, where y is the distance fallen in feet and t is the time in seconds.

To find the average speed during the first 4 seconds of the fall, we need to calculate the total distance fallen and divide it by the total time elapsed.

First, let's find the distance fallen in the first 4 seconds.

Substitute t = 4 into the equation y = 16t^2:

y = 16 * (4^2)

y = 16 * 16

y = 256 ft

Next, let's find the total time elapsed, which is 4 seconds.

Now, we can calculate the average speed.

Average speed = total distance / total time

Average speed = 256 ft / 4 s

Average speed = 64 ft/s

Therefore, the watermelon's average speed during the first 4 seconds of the fall is 64 ft/s.