Question

complete and balance the following reaction, assuming an acidic environment, by filling in the missing coefficients and formulas. so2?3(aq) mno4(aq)?so2?4(aq) mno2(s)

Answer 1

To complete and balance the given reaction in an acidic environment, follow the steps outlined below. The balanced equation is given as SO2(g) + 2 MnO4-(aq) + 4 H+(aq) → SO42-(aq) + 2 MnO2(s) + 4 H2O(l).

Step-by-step explanation:

To complete and balance the given reaction in an acidic environment, we need to identify the elements and balance them individually, while also balancing the charges. The reaction is:

SO2(g) + MnO4-(aq) → SO42-(aq) + MnO2(s)

1. First, balance the elements other than oxygen and hydrogen. For sulfur (S), there is one atom on each side of the reaction, so it is already balanced. For manganese (Mn), there is one atom on each side of the reaction, so it is also balanced.
2. Next, balance the oxygen atoms by adding water (H2O) molecules to the side that needs more oxygen. In this case, the left side needs more oxygen, so we can add 4 H2O molecules to balance the oxygen atoms.
3. Balance the hydrogen atoms by adding hydrogen ions (H+) to the side that needs more hydrogen. In this case, the right side needs more hydrogen, so we can add 8 H+ ions to balance the hydrogen atoms.
4. Finally, balance the charges by adding electrons (e-) to the side that has a higher positive charge. In this case, the left side has a higher positive charge, so we can add 8 electrons to balance the charges.

The balanced equation is:

SO2(g) + 2 MnO4-(aq) + 4 H+(aq) → SO42-(aq) + 2 MnO2(s) + 4 H2O(l)

Answer 2

In acidic environment, balance SO₃²⁻ + MnO₄⁻ → SO₄²⁻ + MnO₂ with H⁺ & e⁻: 5SO₃²⁻ + 2MnO₄⁻ + 4H⁺ → 5SO₄²⁻ + 2MnO₂ + 2H₂O + 6e⁻

Here's the balanced reaction step-by-step, assuming an acidic environment:

1. Identify the unbalanced equation:

SO₃²⁻(aq) + MnO₄⁻(aq) → SO₄²⁻(aq) + MnO₂(s)

2. Balance the oxygen atoms:

Add water (H₂O) molecules to balance the oxygen atoms not in sulfate or permanganate ions:

SO₃²⁻(aq) + MnO₄⁻(aq) → SO₄²⁻(aq) + MnO₂(s) + 2 H₂O(l)

3. Balance the hydrogen atoms:

Add protons (H⁺) to balance the hydrogen atoms in the water molecules:

SO₃²⁻(aq) + MnO₄⁻(aq) + 4 H⁺(aq) → SO₄²⁻(aq) + MnO₂(s) + 2 H₂O(l)

4. Balance the charges:

The charges on both sides of the equation are now -2 +4 +4 = +6 and -2 + 0 = -2. Add electrons (e⁻) to balance the charges:

5 SO₃²⁻(aq) + 2 MnO₄⁻(aq) + 4 H⁺(aq) → 5 SO₄²⁻(aq) + 2 MnO₂(s) + 2 H₂O(l) + 6 e⁻

5. Check for balance:

Count the atoms and charges on both sides to ensure they are equal:

Left side: 5 S, 15 O, 2 Mn, 4 H, +4 charge

Right side: 5 S, 15 O, 2 Mn, 4 H, +4 charge

The balanced equation is:

5 SO₃²⁻(aq) + 2 MnO₄⁻(aq) + 4 H⁺(aq) → 5 SO₄²⁻(aq) + 2 MnO₂(s) + 2 H₂O(l)