Question

Point J is on line segment IK. Given JK =2x-1, IK=3x+2,and IJ=3x-5 determine the numerical length of JK

Answer 1

Explanation:

IJ + IK = JK

3x + 2 + 3x - 5 = 2x - 1

6x - 3 = 2x - 1

6x = 2x + 3 - 1

6x = 2x - 2

6x - 2x = 2

4x = 2

x = 2

Now to find the numerical length of JK, plug the value of x back into the measurement given for JK:

JK = 2x - 1 = (2*2) - 1 = 4-1 = 3

So the numerical length of JK is 3.