5.1k views
3 votes
∑ n=1
[infinity]
n( n
+1)
3
n
−1

User Equiman
by
8.0k points

1 Answer

3 votes

Let's try to find out the sum of the series

∑ (n*(n+1))/3^(n−1), from n=1 to infinity.

But first, let's discuss about the type of series this is.

There are many types of series such as arithmetic, geometric, harmonic, etc. One special type is the geometric series, wherein each term equals the previous term multiplied by a constant ratio.

In an infinite geometric series, the sum S can be calculated by the formula S = a / (1 - r), where 'a' is the first term and 'r' is the common ratio.

However, the given series is not a geometric series.

In order to compute the sum of the series, we would need a different method of calculation. But the trouble here is, the given series does not fall under any of the basic types of series that have well-known formulas for computing their sums.

Now, an important concept in series is convergence and divergence. A series is said to converge if the terms of the series approach a specific value. Conversely, a series diverges if the terms do not approach any particular value.

The given series does not appear to approach any particular value, and hence, it diverges. In mathematics, it is generally said that the sum of a diverging series does not exist or is infinite.

Therefore, the sum of the given series does not exist.

User Plagon
by
8.4k points
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