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Give the axis of symmetry and vertex of each equation. y=3(x-2)^(2)+5

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First, we need to identify the form that this equation is in.

The given equation `y=3(x-2)^2+5` is in the form `y=a(x-h)^2+k`. This formula represents a parabolic function where `(h, k)` is the vertex and `x = h` is the axis of symmetry. The values: `h` represents a horizontal shift, `k` represents a vertical shift, and `a` affects the direction and the wideness of the parabola.

Now, let's identify the values of `h` and `k` from the given equation.

From `y=3(x-2)^2+5`, we see that `h` is `2` and `k` is `5`.

So, according to the standard function's form, our parabola will have the following properties:

* The axis of symmetry can be found using the equation `x = h`, substituting `h` gives us x = 2.
* The vertex of the equation is given by the coordinates `(h, k)`, substituting `h` and `k` gives us the point (2, 5).

In conclusion, for the given equation `y=3(x-2)^2+5`, the axis of symmetry is `x = 2`, and the vertex of the parabola is the point `(2, 5)`.

User Rizwan Atta
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