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Write The Equation Of The Circle Centered At (3,-4) With Radius 14.

User Mantas D
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First the equation of the circle should be known :

We want to write the equation of the circle in standard form, which is (x - h)² + (y - k)² = r².

The center of the circle, (h, k), is given as (3, -4). Therefore, h = 3 and k = -4.

The radius of the circle, r, is given as 14.

Substituting h = 3, k = -4, and r = 14 into the equation, we have :

(x - 3)² + (y - (-4))² = 14²
Simplifying the equation gives us the result :

(x - 3)² + (y + 4)² = 196

So, the equation of the circle centered at (3, -4) with radius 14 is (x - 3)² + (y + 4)² = 196.

User Kybazzi
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