Answer:
C
Step-by-step explanation:
The bonding in molecules can be classified into different types, such as sigma (σ) bonding, pi (π) bonding, and delta (δ) bonding. In this case, we are looking for an ion that does not involve pi (π) bonding.
(a) SO3: In the case of SO3, the sulfur atom is bonded to three oxygen atoms. Each oxygen-sulfur bond consists of one sigma (σ) bond and two pi (π) bonds. Therefore, SO3 involves pi (π) bonding.
(b) XeO3: In XeO3, the xenon atom is bonded to three oxygen atoms. Each oxygen-xenon bond consists of one sigma (σ) bond and two pi (π) bonds. Therefore, XeO3 involves pi (π) bonding.
(c) SO2: In SO2, the sulfur atom is bonded to two oxygen atoms. Each oxygen-sulfur bond consists of one sigma (σ) bond, but there are no pi (π) bonds involved. Therefore, SO2 does not involve pi (π) bonding.
(d) XeOF4: In XeOF4, the xenon atom is bonded to four fluorine atoms and one oxygen atom. The xenon-oxygen bond consists of one sigma (σ) bond, but there are no pi (π) bonds involved. Therefore, XeOF4 does not involve pi (π) bonding.
Based on the above analysis, the ion that does not involve pi (π) bonding is option (c) SO2.