Question

Find the midpoint of the line segment with the following endpoints.

The midpoint of line segment P₁P₂ is.
(Simplify your answer. Type an ordered pair.)
P₁:
= (1-12) ²² (-1²-17)
P₂:
3'12
3
12

Answer 1

(-2/3, 1/2)

Explanation:

To find the midpoint between two points, we can use the midpoint formula, which states that the midpoint (M) between two points (x₁, y₁) and (x₂, y₂) is given by:

M = ((x₁ + x₂) / 2, (y₁ + y₂) / 2)

Let's apply this formula to the given points: (7/3, 5/12) and (-11/3, 7/12).

• x₁ = 7/3
• y₁ = 5/12
• x₂ = -11/3
• y₂ = 7/12

Using the midpoint formula:

• M = ((x₁ + x₂) / 2, (y₁ + y₂) / 2)
• = (((7/3) + (-11/3)) / 2, ((5/12) + (7/12)) / 2)
• = ((-4/3) / 2, (12/12) / 2)
• = (-2/3, 1/2)

Therefore, the midpoint of the line segment connecting (7/3, 5/12) and (-11/3, 7/12) is (-2/3, 1/2).

Answer 2

Explanation:

To find the midpoint of a line segment, we can use the midpoint formula, which states that the midpoint (M) is the average of the x-coordinates and the average of the y-coordinates of the endpoints.

Given the endpoints P₁ and P₂:

P₁ = (1, -12, -17)

P₂ = (3, 12, 3)

To find the x-coordinate of the midpoint:

x-coordinate of M = (x-coordinate of P₁ + x-coordinate of P₂) / 2

= (1 + 3) / 2

= 4 / 2

= 2

To find the y-coordinate of the midpoint:

y-coordinate of M = (y-coordinate of P₁ + y-coordinate of P₂) / 2

= (-12 + 12) / 2

= 0 / 2

= 0

Therefore, the x-coordinate of the midpoint is 2, and the y-coordinate of the midpoint is 0.

The midpoint of line segment P₁P₂ is (2, 0).