Answer:
n=210^9.
Step-by-step explanation:
The question is asking for the largest 'n' for which one can solve a problem in one second using an algorithm that requires f(n) bit operations, where each bit operation is carried out in 10-9 seconds, given that f(n)=log n (base 2).
Given that each operation requires 10-9 seconds, we can solve 109 operations in one second. Therefore, we need to solve for n in the equation f(n)=109, which is log2n=109. The solution to this is n=210^9. Hence, the largest 'n' for which one can solve the problem in one second using the given algorithm is 210^9 (option d).