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From the following data, plot both Langmuir and Freundlich isotherms and determine the empirical coefficients. Which isotherm is the best fit?

Initial groundwater concentration of dichromate = 74 mg/L
From the following data, plot both Langmuir and Freundlich isotherms and determine the empirical coefficients. Which isotherm is the best fit? Initial groundwater concentration of dichromate \( =74

1 Answer

5 votes

Answer:

The Langmuir and Freundlich isotherms can be plotted and their empirical coefficients computed using their respective formulas. The isotherm representing the best fit is the one that provides the highest squared correlation coefficient (R² closest to 1) when the adsorption data is plotted.

Step-by-step explanation:

The Langmuir and Freundlich isotherms are used to describe the adsorption characteristics, especially for water pollutants. Unfortunately, there is no possibility to plot these isotherms on a graph. However, I can guide you on how to proceed.

For Langmuir isotherm, it is represented by the formula: C/q = 1/(Qb) + C/Q, where q is the amount of solute adsorbed per unit mass of adsorbent, C is the equilibrium concentration, Q is the amount of solute adsorbed to form a monolayer on the surface of the adsorbent, and b is the empirical constant associated with heat of adsorption. You'll have to perform the necessary computations to determine Q and b.

On the other hand, the Freundlich isotherm: log q = log K + 1/n log C, where K and 1/n are Freundlich constants related to adsorption capacity and intensity, respectively. Again, perform the necessary calculations to determine these.

After plotting the adsorption data on relevant plots (C/q versus C for Langmuir and log q versus log C for Freundlich), the isotherm that provides the best linear fit with highest squared correlation coefficient (R² closest to 1) would be the best fit.

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