Answer:
To calculate the number of moles of hydrogen in 0.448 liters of hydrogen gas at STP (Standard Temperature and Pressure), we need to use the ideal gas law equation, which is PV = nRT. In this equation, P represents the pressure, V represents the volume, n represents the number of moles, R is the ideal gas constant, and T represents the temperature.
At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K). The ideal gas constant, R, is equal to 0.0821 liter·atm/(mol·K).
Given that the volume is 0.448 liters and using the values for pressure and temperature at STP, we can rearrange the ideal gas law equation to solve for n:
n = PV / RT
Substituting the known values:
n = (1 atm) * (0.448 L) / (0.0821 L·atm/(mol·K)) * (273.15 K)
Simplifying:
n = 0.448 / 22.414
n ≈ 0.02 moles
Therefore, there are approximately 0.02 moles of hydrogen in 0.448 liters of hydrogen gas at STP.
Step-by-step explanation: