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If 2x + 13 = 17, find the value of 3x+1

User Markom
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2 Answers

3 votes

Explanation:

2x + 13 = 17

2x = 4

x = 2

3x + 1 = 3×2 + 1 = 6 + 1 = 7

we could have also gone the way to bring both equations to the same base of x. that means we have to multiply the first equation by 3/2, so that it also bases on 3x :

(3/2)×2x + (3/2)×13 = (3/2)×17

3x + 39/2 = 51/2

and we compare this to

3x + 1

so, we still need to subtract 37/2 in the first equation on both sides to get the same left side :

3x + 39/3 - 37/2 = 51/2 - 37/2

3x + 2/2 = 14/2

3x + 1 = 7

as you can see, we get the same result, of course.

User Kuldeep Dubey
by
8.8k points
4 votes

Answer: 7

Explanation:

First, I am going to solve the equation for x.


\underline{\textsc{Given Equation:}}

2x + 13 = 17

Subtract 13 from both sides:


\sf{2x=17-13}


\sf{2x=4}

Divide both sides by 2:


\sf{x=2}

Now, substitute 2 into 3x + 1:

3(2) + 1 = 6 + 1 = 7

Therefore, the value of 3x + 1 when x = 2 is 7.

User Xanderu
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8.0k points

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