Question

carbon dioxide gas evolve during the fermentation of sugar which was collected at 22.5°C and 0.945 ATM after perfect strangers in the volume was found to be 25.0 ML how many grams of carbon dioxide were collected

Answer 1

0.043 grams

Step-by-step explanation:

We can find the mass of carbon dioxide as follows:

`m = n*M`

Where:

n: is the number of moles

M: is the molar mass = 44.01 g/mol

First, we need to calculate the number of moles. We can use the Ideal gas equation:

`PV = nRT`

Where:

P: is the pressure = 0.945 atm

V: is the volume = 25.0 mL

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the tempearture = 22.5 °C

`n = (PV)/(RT) = (0.945 atm*25 mL*(1 L)/(1000 mL))/(0.082 L*atm/K*mol*(22.5 + 273) K) = 9.75 \cdot 10^(-4) moles`

Hence, the mass is:

`m = 9.75 \cdot 10^(-4) moles*44.01 g/mol = 0.043 g`

Therefore, 0.043 grams were collected.

I hope it helps you!