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Equation of a circle with a center of (-2,0) and radius of 3

User Jacob Wang
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The equation of a circle centered at $(a, b)$ with radius $r$ is given by:

$$(x - a)^2 + (y - b)^2 = r^2$$

In this case, we have:

* Center: $(-2, 0)$

* Radius: $3$

So, the equation of the circle is:

$$((x + 2)^2 + y^2) = 9$$

This can be simplified further as:

$$(x + 2)^2 = 9 - y^2$$

Or,

$$(x + 2)^2 = 6$$

Therefore, the equation of the circle with center at $(-2, 0)$ and radius of $3$ is:

$$(x + 2)^2 = 6$$

User Vinzdef
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