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4 votes
If LDH=(2/3x-7), HDF=12 degrees and LDF= (1/3x+32) what is the value of x?

User Robin B
by
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1 Answer

4 votes

Hello!

Answer:


\Large \boxed{\sf x = 143}

Explanation:

→ We want to find the value of x in this triangle.

→ We know that in a triangle, the sum of the angles is equal to 180°.

→ So we have this equation:


\sf (2)/(3)x-7 + 12 +(1)/(3)x +32 = 180

→ Let's solve this equation to find the value of x in the triangle:

Simplify the left side:


\sf (2x)/(3) +(x)/(3) +37 = 180


\sf (3x)/(3) +37 = 180


\sf x +37 = 180

Subtract 37 from both sides:


\sf x +37-37 = 180-37

Simplify both sides:


\boxed{\sf x = 143}

Conclusion:

In this triangle, x is equal to 143.

User Adamdehaven
by
9.0k points

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