Question

Triangle ABC is shown on a coordinate plane.
which statement is true? select all that apply.

Answer 1

A is at (3, 4), B is at (4, 1), C is at (-2, 1).

AB = √((4 - 3)² + (1 - 4)²) = √(1² + (-3)²)

= √(1 + 9) = √10

AC = √((3 - (-2))² + (4 - 1)²) = √(5² + 3²)

= √(25 + 9) = √34

BC = 6

Perimeter of ∆ABC = 6 + √10 + √34

= about 15

Area of ∆ABC = (1/2)(6)(3) = 9

A, B, D, and E are correct.