Answer: -10
Explanation:
What the question is asking; is to find f of g; when the x in g is replaced with a 1; as f(g(1)) states. (the 1 is in the g)
We can start by placing x in the equation of g.
g(x)=(2*1)^2-(6*1)-3
g(x)=4-6-3
g(x)=-5
Now that we have g(x) as 5, we can plug this into f(x). This works ONLY when x is 1, in the eq for G.
f(x)=-5-5
f(x)=-10.