Question

Mr. singh usually deposits $25 into his bank account every week. For the next 8 weeks, he wants to deposit more than the usual $25, and he wants the extra amount deposited to be the same each week. Which inequality and solution show how much more he can deposit each week, 2, and keep the total of his deposits above $500 for those 8 weeks?

Answer 1

To find the solution, we can set up an inequality. Let's say Mr. Singh wants to deposit an extra amount of $x each week. The total amount he deposits in 8 weeks would be greater than $500. The inequality would be: 25 + 8x > 500.

Answer 2

To deposit more than $25 each week and keep the total of his deposits above $500 for the next 8 weeks, Mr. Singh needs to deposit an extra amount greater than $59.38 per week.

Step-by-step explanation:

To find out how much more Mr. Singh can deposit each week, we need to determine the amount that will keep the total of his deposits above $500 for the next 8 weeks.

Let's assume that the extra amount he deposits each week is x. So, his deposits for the next 8 weeks would be the sum of his usual deposit ($25) and the additional deposit (x) multiplied by the number of weeks (8). This sum should be greater than $500:

25 + 8x > 500

To solve this inequality for x, we can subtract 25 from both sides:

8x > 500 - 25

8x > 475

Finally, we divide both sides by 8 to solve for x:

x > 475/8

Therefore, Mr. Singh can deposit more than $25 each week as long as the extra amount is greater than $59.38 (rounded to two decimal places), keeping the total of his deposits above $500 for the next 8 weeks.