In the straightedge and compass construction of the angle bisector below,
which of the following reasons can you use to prove that DGB LEGB?
B
F
E
A. BD BE because they are radii of the same circle, DG = EG
because they are sides of the equilateral triangle DEG, and
BG BG by the reflexive property. Therefore, BDG BEG by SSS
and DGB LEGB by CPCTC.
B. BD BE because they are radii of the same circle, DG EG
because they are sides of the equilateral triangle DEG, and
BG BG by the reflexive property. Therefore, BDG BEG by SSA
and DGB ZEGB by CPCTC.
C. BD BE because they are radii of the same circle, DG EG
because they are sides of the equilateral triangle DEG, and
A
BG BG by the reflexive property. Therefore, BDG BEG by AAS
and DGB LEGB by CPCTC.
Ele
D. BD BE because they are radii of the same circle, DG EG
because they are sides of the equilateral triangle DEG, and
EVE
BG BG by the reflexive property. Therefore, BDG SABEG by SAS
and DGB ZEGB by CPCTC.