So, the acceleration of the bicycle is approximately -1.67 m/s² or it can be said to be decelerating approximately 1.67 m/s².
Introduction
Hi ! Here I will help material about linear motion changes regularly, which is where you will hear a lot of the term acceleration. Acceleration occurs when an object's speed increases in a certain time interval. Acceleration can be negative which is called deceleration. The relationship between acceleration with velocity and time is manifested in the equation:

With the following conditions :
- a = acceleration (m/s²)
= object's final velocity (m/s)
= object's initial velocity (m/s)- t = interval of the time (s)
Problem Solving
We know that :
= object's final velocity = 4 m/s
= object's initial velocity = 12 m/s- t = interval of the time = 4.8 s
What was asked :
- a = acceleration = ... m/s²
Step by step :




So, the acceleration of the bicycle is about -1.67 m/s² or it can be said to be decelerating around 1.67 m/s².