Answer:
Explanation:
It seems like you want to create a set of six points with the strongest possible linear association using the given points (−1, -3) and (–9, -6). To create a strong linear association, you can use these two points and calculate additional points along the line that passes through them. Here's how you can do it:The given points are:
(−1, -3) and (–9, -6)The slope of the line passing through these points is:
m=y2−y1x2−x1m=x2−x1y2−y1Substitute the values:
m=−6−(−3)−9−(−1)=−38m=−9−(−1)−6−(−3)=−83So, the equation of the line is:
y=−38x+by=−83x+bNow, plug in one of the given points to solve for the y-intercept bb:
−3=−38⋅(−1)+b−3=−83⋅(−1)+b
−3=38+b−3=83+b
b=−278b=−827Now you have the equation of the line:
y=−38x−278y=−83x−827Now you can calculate additional points along this line. Choose various x-values and calculate the corresponding y-values using the equation. For example:Let's choose x = 0:
y=−38⋅0−278=−278y=−83⋅0−827=−827So, one additional point is (0, -27/8).Repeat this process to get a set of six points that lie on the line and have a strong linear association.