138k views
3 votes
I don’t get it, A2 G11

I don’t get it, A2 G11-example-1

2 Answers

4 votes

Answer:

Explanation:

The answer is 127

User Patneu
by
7.6k points
2 votes

Answer:

127

Explanation:

The given sequence is an arithmetic sequence because the difference between consecutive terms is constant.

The common difference is 3, so the 32nd term is equal to the first term plus 31 times the common difference, or 34 + 31 × 3 = 127.

General formula for the nth term of an arithmetic sequence:


\sf t_n = a + d(n - 1)

where

  • tn is the nth term
  • a is the first term
  • d is the common difference
  • n is the number of terms

In this case, we have:

tn = 32nd term

a = 34 (first term)

d = 3 (common difference)

n = 32 (number of terms)

Plugging these values into the formula, we get:


\begin{aligned} t_n&\sf = 34 + 3(32 - 1) \\\\&\sf = 34 + 3* 31\\\\ &\sf = 34+93\\\\ &\sf = 127 \end{aligned}

Therefore, the 32nd term of the sequence is 127.

User Andershqst
by
8.0k points