Answer:
Explanation:
Let's break down the information given:
1. One-third of the employees have a university degree.
2. Half of the employees with a university degree are men.
3. 40% of the employees without a university degree are women.
4. 102 employees are men.
Let's define some variables:
- Let E be the total number of employees.
- Let D be the number of employees with a university degree.
- Let ND be the number of employees without a university degree.
- Let M be the number of male employees.
- Let W be the number of female employees.
Given information:
1. D = (1/3) * E
2. M = (1/2) * D
3. W = 0.4 * ND
4. M = 102
Since half of the employees with a university degree are men (2nd point), we can substitute D from the 1st point into the 2nd point:
M = (1/2) * D = (1/2) * (1/3) * E = (1/6) * E
Since the number of male employees is given as 102 (4th point), we can equate M to 102:
(1/6) * E = 102
Now we can solve for E:
E = 102 * 6
E = 612
Now we can find D (employees with a university degree) and ND (employees without a university degree):
D = (1/3) * E = (1/3) * 612 = 204
ND = E - D = 612 - 204 = 408
Since 40% of the employees without a university degree are women (3rd point), we can find W:
W = 0.4 * ND = 0.4 * 408 = 163.2
Since the number of employees must be a whole number, we can assume that the number of female employees is rounded up to the nearest whole number (since we can't have a fraction of a person):
W = 164
Therefore, there are 164 female employees in the company.