Question

A car accelerates 6m/s to 8m/s in 12 sec assuming the acceleration to be uniform calculate the a) acceleration b)distance covered by car in 12 sec

Answer 1

these are my answers

Answer 2

Answer: Acceleration = 1m/s2 and Distance = 144 metres

Explanation: Initial Velocity(u) = 6m/s (Speed at the Beggining)
Final Velocity(v) = 8m/s (Speed at the End)

Time = 12 Seconds

There is a formula to calculate Acceleration... Lets apply that..

Acceleration = Final Velocity - Initial Velocity/Time

In short cut

Acceleration = v-u/time

v= Final Velocity

u= Initial Velocity

Acceleration = 8m/s - 6m/s/12

Acceleration = 2m/s divided by 2

2 divided by 2 = 1.. Soo,

Acceleration = 1m/s2

Lets Calculate Distance now...

There is a formula for that too...

Distance(s)= (u x t) + a x t x t/2
Distance(s)= (6 x 12) + 1 x 12 x 12/2

Distance(s)= 72 + 144/2

Distance(s)= 72 + 72

Distance(s)= 144 Metres