Question

How many grams of NaN3 are required to form 5.00g of nitrogen gas

Answer 1

i believe 7.74. Correct me if I am wrong.

Step-by-step explanation:

5.00g N2 x (1 mol N2 / 28.00g N2) x (2 mol NaN3 / 3 mol N2) x (64.99g NaN3 / 1 mol NaN3) = 7.74g NaN3