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How many grams of NaN3 are required to form 5.00g of nitrogen gas

User Rosebud
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1 Answer

3 votes

Answer:

i believe 7.74. Correct me if I am wrong.

Step-by-step explanation:

5.00g N2 x (1 mol N2 / 28.00g N2) x (2 mol NaN3 / 3 mol N2) x (64.99g NaN3 / 1 mol NaN3) = 7.74g NaN3

User Javeed Ishaq
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