Answer:
x = 0 OR x = - 3
Explanation:
re-arrange formula to make y the subject:
y = 10-6x and y = x^2 - 3x + 10
sub in values of y:
10 - 6x = x^2 - 3x + 10
re-arrange to write in terms of quadratic formula:
x^2 - 3x + 6x + 10 - 10 = 0
x^2 + 3x + 0 = 0
A B C
use factorisation or quadratic formula (screenshot given) to come to the solution:
(x+0)(x + 3) or (x)(x+3)
x= +/- 0 OR x = -3
Hope this helps :)