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Z⁸+Z⁴+1 solve factorize

User Arturo Sbr
by
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1 Answer

3 votes

Answer:


\sf\\z^8+z^4+1\\\\=z^8+2z^4+1-z^4\\\\=(z^4+1)^2-(z^2)^2\\\\=(z^4+z^2+1)(z^4-z^2+1)\\\\=[z^4+2z^2+1-z^2](z^4-z^2+1)\\\\=[(z^2+1)^2-z^2](z^4-z^2+1)\\\\=(z^2+z+1)(z^2-z+1)(z^4-z^2+1)

User Russell Newquist
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