What is the force per meter of length on a straight wire carrying a 6.40-A current when perpendicular to a 0.90-T uniform magnetic field?

asked May 12, 2024 82.9k views

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by Likk

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Answer:

F = I L B force on wire perpendicular to field B

F / L = I B = 6.4 * .90 = 5.76 N/m

Quux answered May 19, 2024

by Quux

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