Question

(b) The maximum power of a car mass 1200 kg when it is travelling at a constant velocity of 30 m s" is 90 kW. Calculate the forward thrust force of car's engine when the car is car travelling at 30 ms.

Answer 1

I got 6000N as my answer.

Step-by-step explanation:

m = 1200

v = 30m/s

u = 0m/s

p = 90kW : 90,000W

½m(v²-u²)

½ x 1200(30 x 30 - 0)

½ x 1200 x 900

½ x 1080000 = 540000j

p = e/t : t = e/p

t = 540000/90000

t = 6secs

a = v/t

a = 30/6

a = 5

F = ma

F = 1200 x 5

F = 6000N