Question

Find the zeros of f(x) =x^3 +6x^2 + 8x

Answer 1

-2, 0, 4

Explanation:

First, take out the common factor of x

x(x^2 + 6x + 8) = 0

Then the quadratic equation can be factored

x(x + 4)(x + 2) = 0

This means

x = 0

x + 4 = 0

x + 2 = 0

So, the zeros are -2, 0, and 4