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Find the zeros of f(x) =x^3 +6x^2 + 8x

User Shmee
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1 Answer

5 votes

Answer:

-2, 0, 4

Explanation:

First, take out the common factor of x

x(x^2 + 6x + 8) = 0

Then the quadratic equation can be factored

x(x + 4)(x + 2) = 0

This means

x = 0

x + 4 = 0

x + 2 = 0

So, the zeros are -2, 0, and 4

User Albert Prats
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8.6k points

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