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A compound with the molar mass 162 g/mol has an empirical formula of c5h7n. what is the molecular formula of the compound?

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Final answer:

The compound with a molar mass of 162 g/mol and an empirical formula of C5H7N has a molecular formula of C10H14N2, determined by dividing the molar mass of the compound by the empirical formula mass and multiplying the result with the empirical formula.

Step-by-step explanation:

To determine the molecular formula of a compound with a given empirical formula, we need to compare the molar mass of the empirical formula to the molar mass of the compound.

In this case, the empirical formula C5H7N has a molar mass of 81.13 g/mol. If the compound's molar mass is 162 g/mol, we can find out how many times the empirical formula mass fits into the molar mass of the compound.

Divide the molar mass of the compound by the molar mass of the empirical formula (162 g/mol ÷ 81.13 g/mol).

The result is approximately 2, which indicates that the empirical formula must be multiplied by 2 to get the molecular formula.

Therefore, the molecular formula of the compound is C10H14N2.

User JPReddy
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5 votes

Final answer:

The molecular formula of the compound with an empirical formula of C5H7N and a molar mass of 162 g/mol is C10H14N2.

Step-by-step explanation:

The empirical formula of the compound is C5H7N, and its molar mass is 162 g/mol. To determine the molecular formula, we need to find the integer multiple, n, by dividing the molar mass of the compound by the empirical formula mass. The empirical formula mass of C5H7N is 81.13 g/mol. Dividing 162 g/mol by 81.13 g/mol gives us a value of approximately 2. Therefore, the molecular formula of the compound is 2 times the empirical formula, which is C10H14N2.

User David Nedrow
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8.6k points