Answer:
|−16| is greater
Explanation:
I x I where x can be any number—>
I x I indicates that we have to find the absolute value of the number, now absolute value is the number’s distance from 0
So:
|−16| = 12 (as minus 12 is 12 spaces away from 0)
|−16| = 16 (as minus 16 is 16 spaces away from 0)
thus, 12 < 16 and so |−16| > |−12|