Question

S(-4,-6) is the midpoint T(-7,-3) find R

Answer 1

(-1, -9).

Explanation:

Midpoint formula:

M(x_m, y_m) = ((x_A + x_B) / 2, (y_A + y_B) / 2)

Given that S(-4, -6) is the midpoint of line segment TR and we know the coordinates of T(-7, -3), we can use the midpoint formula to solve for R:

M(x_m, y_m) = ((x_T + x_R) / 2, (y_T + y_R) / 2)

Substituting in the given coordinates:

(-4, -6) = ((-7 + x_R) / 2, (-3 + y_R) / 2)

Now we can solve for the coordinates of R:

-4 = (-7 + x_R) / 2

-6 = (-3 + y_R) / 2

Solve for x_R and y_R:

-7 + x_R = -8

x_R = -1

-3 + y_R = -12

y_R = -9

So, the coordinates of point R are (-1, -9).