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Find the zeros of g(x) = 4x³ + 13x² - 37x10, given its graph.

=
(1 point)
x = {-5,2}
x={-10,-5, -1/4,2}
x={-10, -5,2}
x={-5,-1/4,2}

Find the zeros of g(x) = 4x³ + 13x² - 37x10, given its graph. = (1 point) x = {-5,2} x-example-1
User Junho Park
by
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1 Answer

2 votes

Answer:

Hi,

Explanation:


4x^3+13x^3-37x-10\\=4x^3-8x^2+21x^2-42x+5x-10\\=4x^2(x-2)+21x(x-2)+5(x-2)\\=(x-2)(4x^2+21x+5)\\=(x-2)(4x^2+20x+x+5)\\=(x-2)(4x(x+5)+(x+5))\\=(x-2)(x+5)(4x+1)\\Zeros\ are\ x=2, x=-5, x=-(1)/(4) \\\\

User Anuraj
by
8.6k points

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