Question

X-3/x-1+6/x-3 thanks in advance

Answer 1

`(x^2 + 3)/(x^2 - 4x + 3)`

Explanation:

This expression means this:

`x - (3)/(x) - 1 + (6)/(x) - 3`

The result is
`x + (3)/(x) + 4`,

but I don't think that is what you mean.

Be careful with expressions with fractions. You may need to use parentheses.

I think you mean this:

`(x - 3)/(x - 1) + (6)/(x - 3) =`

This is an addition of fractions. You need a common denominator. The LCD of x - 1 and x - 3 is (x - 1)(x - 3).

`= ((x - 3)(x - 3))/((x - 1)(x - 3)) + (6(x - 1))/((x - 3)(x - 1))`

`= (x^2 - 6x + 9)/((x - 1)(x - 3)) + (6x - 6)/((x - 1)(x - 3))`

`= (x^2 - 6x + 9 + 6x - 6)/((x - 1)(x - 3))`

`= (x^2 + 3)/(x^2 - 4x + 3)`