Question

Given that log3=0.4771 and log5=0.6990, evaluate the value of log1.35+log2.25

Answer 1

0.4825

Explanation:

log 1.35 + log 2.25

`=log((3^3*5)/(10^2) )+log((3^2*5^2)/(10^2) )`

`=log3^3+log5-log10^2+log3^2+log5^2-log10^2`

`=3* log3+log5-2* log10+2* log3+2* log5-2* log10`

`=5* log3+3* log5-4* log10`

`=5*0.4771+3*0.6990-4`

`=0.4825`