Question

On Tuesday, a local hamburger shop sold a combined total of 438 hamburgers and cheeseburgers. The number of cheeseburgers sold was two times the number

of hamburgers sold. How many hamburgers were sold on Tuesday?

Answer 1

146 hamburgers

Explanation:

Let's call the number of hamburgers sold "H" and the number of cheeseburgers sold "C."

According to the information given in the problem:

The number of cheeseburgers sold was two times the number of hamburgers sold.

This can be expressed as:

`\sf C = 2H`

The combined total of hamburgers and cheeseburgers sold was 438.

This can be expressed as:

`\sf H + C = 438`

Now, we have a system of two equations:

`\sf C = 2H`

`\sf H + C = 438`

We can solve this system of equations using the substitution method.

Substitute the value of C from the first equation into the second equation:

`\sf H + 2H = 438`

Combine like terms:

`\sf 3H = 438`

Divide both sides by 3 to solve for H:

`\sf (3H)/(3)= ( 438)/(3)`

`\sf H = 146`

So, 146 hamburgers were sold on Tuesday.