Answer: ok lets solve this
Explanation:
To find the set A′ (the complement of set A), you need to determine all the elements that are in the universal set U but not in set A. In this case, the universal set U is defined as the set of natural numbers (N) that are less than or equal to 9. Set A is given as {3, 6, 7, 2}.
Explanation:
Identify the Universal Set U: The universal set U is defined as x , which means it consists of all natural numbers that are less than or equal to 9.
Identify Set A: Set A is given as {3, 6, 7, 2}.
Find the Complement of Set A (A′): To find the complement of set A, you need to determine all the elements in the universal set U that are not in set A.
The elements in set A are {3, 6, 7, 2}.
The elements in the universal set U are {1, 2, 3, 4, 5, 6, 7, 8, 9}.
Now, let's find the elements that are in U but not in A:
Elements in U - Elements in A = {1, 4, 5, 8, 9}
Write the Resultant Set A′: The set A′, which is the complement of set A, is {1, 4, 5, 8, 9}.
So, the complement of set A (A′) is {1, 4, 5, 8, 9}. These are the elements in the universal set U that are not present in set A.