Answer:
4.1 m/s (two sig figs)
Explanation:
Honestly, this might have been more physics but oh well.
Given:
Vertical displacement (y) = 2.8 meters
Horizontal displacement (x) = 2.7 meters
Acceleration due to gravity (g) is approximately 9.81 m/s²
Vertical Component:
Using the equation for vertical displacement:
y = v_0y * t - 0.5 * g * t^2
When reaching the highest point (half of the total time), y = 1.4 meters:
1.4 = v_0y * (t / 2) - 0.5 * g * (t / 2)^2
Horizontal Component:
Using the equation for horizontal displacement:
x = v_0x * t
Connecting the Components:
From the horizontal equation, solve for t:
t = x / v_0x
Substitute this t value into the vertical equation:
1.4 = v_0y * (x / v_0x) - 0.5 * g * (x / v_0x)^2
Solve this equation for v_0x, the speed at which she leaves the board.
Rounded to two significant figures, the speed is approximately 4.1 m/s.