Question

If g(x) = x/(sqrt(x + 2)) find the following
9g(a)
1/2g(6a)
g(a^2)
[g(a)]^2

Answer 1

`g(x) = (x)/( √(x + 2) )`

`9g(a) = (9a)/( √(a + 2) )`

`(1)/(2) g(6a) = (1)/(2) ( (6a)/( √(6a + 2) ) ) = (3a)/( √(6a + 2) )`

`g( {a}^(2) ) = \frac{ {a}^(2) }{ \sqrt{ {a}^(2) + 2 } }`

`{(g(a))}^(2) = {( (a)/( √(a + 2) )) }^(2) = \frac{ {a}^(2) }{ a + 2}`