Explanation:
Part 1
a) perimeter of the proposed parking lot
perimeter = sum of all sides
x + (x - 5) + x + 15 + x + 2x + 15 + (2x - 5)
x + x - 5 + x + 15 + x + 2x + 15 + 2x - 5
8x + 20
b) x = 2
8(2) + 22 = 16 + 22 = 38 cm
therefore, if x = 2 than perimeter of the proposed parking lot will be 38 cm.
PART 2
a) area of proposed parking lot
area of I + area of II
area = length × width
length and width of I is x - 5 and x respectively
therefore,
area of I = x ( x - 5) = x² - 5x
area of II = Length × width
length and width of II is 2x + 15 and x respectively.
therefore,
area of II = x(2x + 15) = 2x² + 15x
now,
area of the proposed parking lot is
x² - 15x + 2x² + 15x = 3x²
b) if x = 2
3(2)² + 10(2) = 3(4) + 20 = 12 + 20 = 32 cm²
therefore, is x = 2 than the area of proposed parking lot will be 32cm².