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The principal would like to assemble a committee of 9 students from the 20-member student council. How many different committees can be chosen

User Withheld
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4 votes

Answer:

167960 different committiees can be chosen

Explanation:

We use the combinatorial formula,

The number of combinations of k objects from a set with n objects is n Choose k, or,


n!/(k!)(n-k)!\\

Here, we have to choose 9 students so k = 9 and a total of 20 so n = 20,

which gives,


20!/(9!)(20-9)!\\=20!/(9!)(11!)\\= 167960

User James Foster
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