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Where would the limit exist

Where would the limit exist-example-1

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Answer:

f(1) = 0 when x ≥ 1, so:

1² + 3b(1) + 2b² = 0

2b² + 3b + 1 = 0

(2b + 1)(b + 1) = 0

b = -1, -1/2

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