A gas P diffuses five times rapidly on another gas Q. Calculate the ratio of molecular mass of P and Q

Question

asked Nov 17, 2024 212k views

1 Answer

Kayser · Answer 1 · 2024-11-23T03:43:37+0000

Answer:

1:25

Step-by-step explanation:

We're given:

Let
R_P be the rate of diffusion of gas P, and let
R_Q be the rate of diffusion of gas Q.

R_P=5R_Q

Rate of diffusion is inversely proportional to molar mass:

$(R_P)/(R_Q)=\sqrt{(M_Q)/(M_P)}\\\\(5)/(1)=\sqrt{(M_Q)/(M_P)}\\\\(5^2)/(1)=(M_Q)/(M_P)\\\\(M_Q)/(M_P)=25\\\\(M_P)/(M_Q)=(1)/(25)$

Thus, the ratio of molecular mass of P to Q is 1:25.