Final answer:
An assembly language program for a Boolean calculator requires creating a main procedure to display a menu and handle user input and additional procedures to perform AND, OR, NOT, and XOR operations on hexadecimal numbers.
Step-by-step explanation:
Assembly Language Boolean Calculator
To write an assembly language program that functions as a Boolean calculator for 32-bit integers, we need to create several procedures to handle the user's menu choice and perform the corresponding logic operation. The main procedure should display a menu for the user to choose from operations like AND, OR, NOT, and XOR. Once a choice is made, the program will prompt the user for hexadecimal integers accordingly, then calculate and display the result in hexadecimal form.
Implementing such a program may vary depending on the assembly language dialect and system for which you're writing, such as x86, MIPS, or ARM. Generally, you will be utilizing instructions like AND, OR, XOR, and a bitwise NOT operation. While a full program example is extensive for this format, a snippet of how a procedure may look in x86 assembly is given below:
AND_op PROC
; Prompt for first number
; Read first number into register (e.g., EAX)
; Prompt for second number
; Read second number into register (e.g., EBX)
AND EAX, EBX
; EAX now contains the result
; Convert EAX to a string in hexadecimal
; Display the result
AND_op ENDP
After writing procedures for each operation, the main procedure will handle user input and call the appropriate procedure based on the user's choice. For any assembly program, ensure to test extensively as small errors can be difficult to debug.
Note that the actual implementation will require handling user input and output, converting between hexadecimal and other representations, and more. These tasks might involve system-specific calls or additional assembly language libraries or services.