Question

Find the unknown angles​

Answer 1

`\sf\\\angle PTS=\angle SQT+\angle QST\ \ \ \textsf{[An exterior angle of a triangle is equal to sum of }\\\textsf{opposite interior angles.]}\\\sf{or,\ 80^o=x^o+30^o}\\\sf{or,\ x^o=50^o}`

`\sf\\\angle PQR+\angle QPR = 90^o\ \ \ [PQR\ is\ right\ angled\ triangle.]\\or,\ x^o+y^o=90^o\\or,\ 50^o+y^o=90^o\\\therefore\ y=40^o`